The equation of a transverse travelling ...

The equation of a transverse travelling on a rope is given by `y=10sinpi (0.01x-2.00t)` where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

`63cm//s`

`75cm//s`

`100cm//s`

`121cm//s`

Text Solution

Verified by Experts

The correct Answer is:

The given equation is `y=10sinpi(0.01pix-2pit)`
Hence `omega=` coefficient of `t=2pi`
`implies` maximum speed of the particle `v_(max)=aomega=10xx2pi`
`=10xx2xx3.14=62.8=63(m)/(s)`

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