The frequencies of two sound sources are 256 Hz and 260 Hz, At `t=0` the intesinty of sound is maximum. Then the phase difference at the time `t=1//16` sec will be

Options

A. zero
B. `pi`
C. `pi//2`
D. `(pi)/(4)`

Answer

C

Explanation

Time arrival between two consecutive beats
`T=(1)/(n_1-n_2)=(1)/(260-250)=(1)/(4)`sec so, `(1)/(16)=(T)/(4)`sec
By using time difference `=(T)/(2pi)xx`phase difference
`implies(T)/(4)=(T)/(2pi)xxphiimpliesphi=(pi)/(2)`