A source of sound `S` of frequency 500 Hz situated between a stationary observer `O` and wall `W`, moves towards the wall with a speed of `2m//s`. If the velocity of sound is `332m//s`. Then the number of beats per second heard by the observer is (approximately)

Options

A. `8`
B. `6`
C. `4`
D. `2`

Answer

B

Explanation

For direct sound source is moving away from the observer so frequency heard in this case.
`n_1=n((v)/(v+v_S))=500((332)/(332+2))=500((332)/(334))Hz`
The other sound is echo, reaching the observer from the wall and can be regarded as coming from the image of source formed by reflection at the wall. This image is approaching the observer in the direction of sound. Hence for reflected sound, frequency heard by the observer is
`n_2=n((v)/(v-v_S))=500((332)/(332-2))=500((332)/(330))Hz`
Beats frequency
`=n_2-n_1=500xx332((1)/(330)-(1)/(334))=6`