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An observer moves towards a stationary source of sound, with a velocity one-fifth of the velocity of sound. What is the percentage increase in the apparent frequency?

A

`5`

B

`20`

C

zero

D

`10`

Text Solution

Verified by Experts

The correct Answer is:
B
`f=f_0((v_S+v_O)/(v_S))=f_0[(v+(v)/(5))/(v)]=(6)/(5)f_0`
Percentage increases
`=[((6)/(5)f_0-f_0)/(f_0)]xx100=20%`
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