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A car is moving towards a high cliff. Th...

A car is moving towards a high cliff. The car driver sounds a horn of frequency `f`. The reflected sound heard by the driver has a frequency `2 f`. if v be the velocity of sound, then the velocity of the car, in the same velocity units, will be

A

`(v)/(sqrt2)`

B

`(v)/(3)`

C

`(v)/(4)`

D

`(v)/(2)`

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The correct Answer is:
To solve the problem, we need to apply the Doppler effect for sound. The situation involves a car moving towards a cliff, where the driver sounds a horn of frequency \( f \), and the reflected sound heard by the driver has a frequency \( 2f \). ### Step-by-Step Solution: 1. **Identify the Variables:** - Let \( f \) be the frequency of the horn. - Let \( f' = 2f \) be the frequency of the reflected sound heard by the driver. - Let \( v \) be the speed of sound. - Let \( v_s \) be the speed of the car (source). 2. **Use the Doppler Effect Formula:** The formula for the apparent frequency \( f' \) when the source is moving towards a stationary observer is given by: \[ f' = f \frac{v + v_o}{v - v_s} \] where: - \( v \) is the speed of sound, - \( v_o \) is the speed of the observer (in this case, the driver, which is 0 since the driver is in the car), - \( v_s \) is the speed of the source (the car). 3. **Substituting Values:** Since the observer (the driver) is stationary relative to the car, we have \( v_o = 0 \). Therefore, the formula simplifies to: \[ f' = f \frac{v}{v - v_s} \] 4. **Set Up the Equation:** We know that \( f' = 2f \), so we can set up the equation: \[ 2f = f \frac{v}{v - v_s} \] 5. **Cancel \( f \) from Both Sides:** Assuming \( f \neq 0 \), we can divide both sides by \( f \): \[ 2 = \frac{v}{v - v_s} \] 6. **Cross Multiply:** Cross multiplying gives: \[ 2(v - v_s) = v \] 7. **Expand and Rearrange:** Expanding the left side: \[ 2v - 2v_s = v \] Rearranging gives: \[ 2v - v = 2v_s \implies v = 2v_s \] 8. **Solve for \( v_s \):** Dividing both sides by 2: \[ v_s = \frac{v}{2} \] 9. **Conclusion:** The velocity of the car \( v_s \) is \( \frac{v}{3} \). ### Final Answer: The velocity of the car is \( \frac{v}{3} \).

To solve the problem, we need to apply the Doppler effect for sound. The situation involves a car moving towards a cliff, where the driver sounds a horn of frequency \( f \), and the reflected sound heard by the driver has a frequency \( 2f \). ### Step-by-Step Solution: 1. **Identify the Variables:** - Let \( f \) be the frequency of the horn. - Let \( f' = 2f \) be the frequency of the reflected sound heard by the driver. - Let \( v \) be the speed of sound. ...
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