An object weigh 10 N when measured on the surface of the earth. What would be its weight when measure on the surface of moon ?

Explanation

To find the weight of an object on the surface of the Moon when its weight on the surface of the Earth is given, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Weight on Earth**:
The weight of the object on Earth is given as 10 N. Weight (W) is defined as the product of mass (m) and acceleration due to gravity (g). Thus, we can write:
\[ W_{Earth} = m \cdot g_{Earth} \]
Here, \( W_{Earth} = 10 \, \text{N} \).

2. **Acceleration due to Gravity**:
The acceleration due to gravity on Earth (\( g_{Earth} \)) is approximately \( 9.8 \, \text{m/s}^2 \). However, for simplicity, we can use \( g_{Earth} \approx 10 \, \text{m/s}^2 \).

3. **Calculate Mass**:
Rearranging the equation for weight, we can find the mass of the object:
\[ m = \frac{W_{Earth}}{g_{Earth}} = \frac{10 \, \text{N}}{10 \, \text{m/s}^2} = 1 \, \text{kg} \]

4. **Weight on the Moon**:
The acceleration due to gravity on the Moon (\( g_{Moon} \)) is approximately \( \frac{1}{6} \) of that on Earth. Therefore:
\[ g_{Moon} = \frac{1}{6} g_{Earth} \approx \frac{1}{6} \times 10 \, \text{m/s}^2 \approx 1.67 \, \text{m/s}^2 \]

5. **Calculate Weight on the Moon**:
Now we can calculate the weight of the object on the Moon using the mass we found:
\[ W_{Moon} = m \cdot g_{Moon} = 1 \, \text{kg} \cdot \left(\frac{1}{6} \cdot 10 \, \text{m/s}^2\right) = \frac{10}{6} \, \text{N} = \frac{5}{3} \, \text{N} \approx 1.67 \, \text{N} \]

### Final Answer:
The weight of the object on the surface of the Moon is approximately \( \frac{5}{3} \, \text{N} \) or \( 1.67 \, \text{N} \).

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