For a body floating on water, apparent weight is equal to :

Options

A. actual weight of the body
B. zero
C. weight of the body minus the weight of the liquid
D. none of the above

Answer

To determine the apparent weight of a body floating on water, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Weight and Buoyant Force**:
- When a body is floating on water, it experiences two main forces: its weight (W) acting downwards and the buoyant force (F_b) acting upwards.
- The weight of the body can be expressed as \( W = mg \), where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity.

2. **Condition for Floating**:
- For an object to float, the buoyant force must equal the weight of the object. This can be expressed mathematically as:
\[ F_b = W \]
- Since the object is in equilibrium (not sinking or rising), the net force acting on it is zero.

3. **Calculating Apparent Weight**:
- The apparent weight (W_a) of the body when it is floating can be defined as the actual weight minus the buoyant force:
\[ W_a = W - F_b \]
- Substituting the condition for floating into this equation:
\[ W_a = W - W = 0 \]

4. **Conclusion**:
- Therefore, the apparent weight of a body floating on water is equal to zero.

### Final Answer:
The apparent weight of a body floating on water is **zero**.

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