(a) How much current will an electric bulb draw from a `220 V` source, if the resistance of the bulb filament is `1200 Omega` ?
(b) How much current will an electric heater draw from a `220 V` source, if the resistance of the heater coil is `100 Omega` ?

Answer

(a) 0.18 A
(b) 2.2 A

Explanation

(a) `I = (V)/(R ) = (220 V)/(1200 Omega) = 0.18 A`
(b) `I = (V)/(R ) = (220 V)/(100 Omega) = 2.2 A`.