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A cylinder of a material is 10 cm long a...

A cylinder of a material is `10 cm` long and has a cross-section of `2 cm^2`. If its resistance along the length be `20 Omega`, what will be its resistivity in numbers and units ?

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The correct Answer is:
`4 Omega cm`
`rho = (RA)/(l) = ((20 Omega)(2 cm^2))/(10 cm) = 4 Omega cm`.
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