Three resistors of `2 Omega, 3 Omega and 4 Omega` are connected in
(a) series
(b) parallel.
Find the equivalent resistance in each case.

Answer

(a) `9 Omega`
`0.92 Omega`.

Explanation

(a) `R_s = 2 Omega + 3 Omega + 4 Omega = 9 Omega`
(b) `(1)/(R_p)=(1)/(2)+(1)/(3)+(1)/(4)=(6 + 4 +3)/(12) = (13)/(12) , R_p = (12)/(13) Omega = 0.92 Omega`.