Three resistors, each of `2 Omega`, are connected together so that their total resistance is `3 Omega`. Draw a diagram to show this arrangement and check it by calculation.

Answer

In the diagram, show a parallel combination of two resistors `2 Omega` each and this combination in series with one resistors of `2 Omega`.

Explanation

The resultant of parallel combination of two resistors (each of `2 Omega`) is `1 Omega`. When this combination is connected in series with the third resistor of `2 Omega`, the resultant resistance `= 1 Omega + 2 Omega = 3 Omega`.