Three resistors of `6 Omega,2 Omega` and `x` are connected in series to a cell of emf `1.5 V`. The current registered is `(1//6) A`. Calculate the value of `x`.

Answer

`1 Omega`

Explanation

As `I = (V)/( R), (1)/(6) = (1.5)/(6 + 2 + x)`
or `8 + x = 9` or `x = 1 Omega`.