A wire whose resistance is `80 Omega`is cut into three pieces of equal lengths which are then arranged in parallel. Calculate the resistance of the combination.

Answer

`8.88 Omega`

Explanation

Resistance of each piece `= (80)/(3) Omega`
Since three pieces of `(80//3) Omega` are in parallel, the resultant resistance of the combination,
`R = ((80//3)Omega)/(3) = 8.88 Omega`.