A soldering rod iron draws an energy of `45000 J` in `4` minutes when the current flowing through its element is `6 A`. Calculate the resistance of its heating element.

Answer

`5.2 Omega`

Explanation

`W = I^2 Rt, R = (W)/(I^2 t) = (45000 J)/((6 A)^2(4 xx 60 s)) = 5.2 Omega`.