`100 J` of heat are produced each second in a `4 Omega` resistance. Find the potential difference across the resistor.

Answer

20 V

Explanation

`H = I^2 rt, I = sqrt((H)/(Rt)) = sqrt((100 J)/(4 Omega xx 1 s)) = 5 A`
`V = IR = 5 A xx 4 Omega = 20 V`
Aliter. `H = (V^2 t)/( R), V = sqrt((HR)/(t)) = sqrt((100 J xx 4 Omega)/(1 s)) = 20 V`.