A current of `1 A` is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in `16` seconds would be roughly :

Options

A. `10^20`
B. `10^10`
C. `10^18`
D. `10^23`

Answer

A

Explanation

As `Q = I t = (1 A)(16 s) = 16 C, n = (Q)/( e) = (16 C)/(1.6 xx 10^-19 C) = 10^20`.