How many par sec are there in one ligth year?

Explanation

As is known 1 ly`=9.46xx10^(15)m`
and `1` par sec=`3.1xx10^(16)m`
`therefore(11y)/(1par sec)=(9.46xx10^(15))/(3.1xx10^(16))=0.305`
` therefore 11y=0.305` par sec