The parallax of a heavenly body measured from tow points diametrically opposite on equator of earth is 2.0 minute. If radius of earth is 6400 km, calculate distance of heavenly body.

Explanation

Here, ` theta =2.0' = (2^@)/(60) = (2)/(60)xx(pi)/(180)radian`
I = diameter of earth = `2xx6400km`
`=1.28 xx10^4km = 1.28xx10^7m.`
r = ?
From ` I = r theta,`
`r = (I)/(theta) = (1.28xx10^7)/(pi//30xx180) = 2.2xx10^(10)m`