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Find the dimensions of K in the relation...

Find the dimensions of K in the relation `T = 2pi sqrt((KI^2g)/(mG))` where T is time period, I is length, m is mass, g is acceleration due to gravity and G is gravitational constant.

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Here, `T = 2pisqrt((K I^2g)/(mG))`
`T^2 = 4pi^2 (KI^2g)/(mG) K = (mGT^2)/(4pi^2I^2 g)`
`K = (M(M^(-1) L^3T^(-2)T^2))/(L^2[LT^(-2)] = [M^0 L^0 T^2]`
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