IF `in_0` is electric permittivity of free space and E is electric field, then show that `in_0E^2` has the dimensions of pressure.

Explanation

If is known that `(1)/(2) in_0E^2` represents energy
density, i.e., energy per unit volume, i.e.,
dimensions of
`in_0E^2 = ("energy")/("volume") = ("force" xx "distance")/("area" xx "length")`
`=("force")/("area") = pressure`