If `x =2 at -5 bt^2,` where x is in metre and t is in seconds, find the dimensions of a//b.

Explanation

Here, `x =2at -5 bt^2`
`:. A = (x)/(t) and b= (x)/(t^2)`
`(a)/(b) = (x)/(t). (t^2)/(x) =t= [M^0L^0T^1]`