A force of `(2500 +- 5)`N is applied over an area of `(0.32 +- 0.02)m^2` Calculate the pressure exerted over the area.

Explanation

Here, `F =(2500 +- 5)N`
`A = (0.32 +- 0.02)m^2, P= ?`
`P = (F)/(A) = (2500)/(0.32) = 7812.5N//m^2`
Now, `(DeltaP)/(P) = +-((DeltaF)/(F) +(DeltaA)/(A)) = +- ((5)/(2500)+(0.02)/(0.32)) = +- (0.002 + 0.0625) = +- 0.0645`
`DeltaP =+- 0.0645 P = +- 0.0645xx7812.5 = +- 503.9N//m^2`