In searle's experiment, the diameter of the wire, as measured by a screw gauge of least count 0.001 cm is 0.500 cm. The length, measured by a scale of least count 0.1cm is 110.0cm. When a weight of 40N is suspended from the wire, its extension is measured to be 0.125 cm by a micrometer of least count 0.001 cm. Find the Young's modulus of the meterial of the wire from this data.

Explanation

To find the Young's modulus of the material of the wire from the given data, we will follow these steps:

### Step 1: Identify the Given Values
- Diameter of the wire, \( d = 0.500 \, \text{cm} = 0.500 \times 10^{-2} \, \text{m} \)
- Length of the wire, \( L = 110.0 \, \text{cm} = 1.10 \, \text{m} \)
- Weight suspended, \( W = 40 \, \text{N} \)
- Extension of the wire, \( \Delta L = 0.125 \, \text{cm} = 0.125 \times 10^{-2} \, \text{m} \)

...