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The resistance R= (V)/(I), where V= (100...

The resistance `R= (V)/(I)`, where `V= (100+-5.0) V` and `I=(10+-0.2)A`. Find the percentage error in `R`.

Text Solution

Verified by Experts

`(DeltaR)/(R )xx100 = +-((DeltaV)/(V) +(DeltaI)/(I))xx100`
`=+-[(5)/(100) +(0.2/10)]xx100=+-7%`
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Knowledge Check

  • If voltage V=(100pm5) V and current I=(10pm0.2) A, the percentage error in resistance R is

    A
    `5.2`%
    B
    0.25
    C
    0.07
    D
    0.1

  • If voltage V = (100 pm 5)V and current I = (10 p, 0.2)A , the percentage error in resistance R is:

    A
    0.052
    B
    0.25
    C
    0.07
    D
    0.1

  • When the voltage and current in a conductor are measured as (100pm4 ) V and (5pm0.2 ) A, then the percentage of error in the calculation of resistance is

    A
    `8%`
    B
    `4%`
    C
    `20%`
    D
    `10%`