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A capacitor C = (2.0 +- 0.1)muF is charg...

A capacitor `C = (2.0 +- 0.1)muF` is charged to a voltage `V = (20 +- 0.5)` volt. Calculate the charge Q with error limits.

Text Solution

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`Q = CV = 2.0xx20 = 40` micro coulomb
`=40xx10^(-6)C`
`(DeltaQ)/(Q) = (DeltaC)/(C ) +(DeltaV)/(V) = (0.1)/(2.0)+(0.5)20 = (3)/(40)`
`DeltaQ = (3)/(40)xxQ = 3.0 muC`
`Hence, Q = (40 +- 3.0)xx10^(-6)C`
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