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The pitch of a screw gauge is 1mm and th...

The pitch of a screw gauge is 1mm and there are 100 divisions on circular scale. While measuring the diameter of a wire, the linear scale reads 1 mm and 47th division on circular scale coincides with reference line. The length of the wire is 5.6 cm. Find the curved surface area of the wire in `cm^2` to correct number of significant figures.

Text Solution

AI Generated Solution

To find the curved surface area of the wire, we will follow these steps: ### Step 1: Calculate the Least Count of the Screw Gauge The least count (LC) of the screw gauge can be calculated using the formula: \[ \text{Least Count} = \frac{\text{Pitch}}{\text{Number of divisions on the circular scale}} \] Given: - Pitch = 1 mm = 0.1 cm (since we need the answer in cm²) ...
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The pitch of a screw gauge is a mm and there are 100 division on the circular scale. While measuring the diameter of a wire, the linear scale reads 1mm and 47th division on circular scale coincides with the reference line. The length of the wire is 5.6 cm. Find the curved surface area (in cm^2) of the wire in proper significant figures.

The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. In measuring the diameter of a sphere there are six divisions on the linear scale and forty divisions on circular scale coincides with the reference line. Find the diameter of the sphere.

Knowledge Check

  • The pitch of a screw guage is 1 mm and there are 100 divisions on the circular scale. While measuring diameter of a thick wire, the pitch scale reads 1 mm and 63rd division on the circular scale coincides with the reference. The length of the wire is 5.6 cm. Then

    A
    The least count of screw guage is 0.001 mm
    B
    The volume of the wire is `0.117 cm^(3)`
    C
    The diameter of the wire is 1.63 m
    D
    The cross-section area of the wire is `0.0209 cm^(3)`

  • The pitch of a screw gauge is 1 mm with 100 divisions on the circular scale. For a given wire, the linear scale reads 2 mm and 64th divisions on the circular scale coincides with the reference line. If the length of the wire is 3.5 cm, find the volume in cm^(3) ?

    A
    `19.0cm^(3)`
    B
    `0.19cm^(3)`
    C
    `76.0cm^(3)`
    D
    `0.76cm^(3)`

  • The pitch of a screw gauge is 1mm and its cap is divided into 100 divisions. When this screw gauge is used to measure the diameter of a wire, then main scale reading is 2 mm and 58^(th) division of circular scale coincides with the main scale. There is no zero error in the screw gage. Then the diameter of the wire is

    A
    `2.38 mm`
    B
    `2.48 mm`
    C
    `2.58 mm`
    D
    `3.58 mm`

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