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The diameter of a brass metal bob is mea...

The diameter of a brass metal bob is measured as `1.92xx10^(-2)m` using a vernier callipers. The mass of the bob is measured to be `29.150xx10^(-3)kg` using a physical balance. Find density of the meterial to correct number of significant figures.

Text Solution

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Here, diameter of bob, `D = 1.92xx10^(-2)m`, and
mass of bob, `m = 29.150xx10^(-3)kg`
volume of bob, `V= (4)/(3)pi r^3 = (4)/(3) pi (D^3)/(8)`
`=(4)/(3)xx(22)/(7) (1.92xx10^(-2))^3/(8) = 3.707xx10^(-6)m^3`
Density of meterial , `rho = (m)/(V)`
` = (29.150xx10^(-3))/(3.707xx10^(-6))kg//m^3`
`rho = 7.863xx10^3kg//m^3`
Rounding off to three significant digits.
`rho = 7.86xx10^3kg//m^3`
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