A star is located 9 ly away from us. What is its distance in par sec ? What is the parallax shown by this star when viewed from two locations `3xx10^(11)m` apart. Given 1 par sec `=3.084xx10^(16)m, and 1ly = 9.46xx10^(15)m.`

Answer

2.76 par sec ; 0.73''

Explanation

`r = 9 ly = 9xx9.46xx10^(15)m`
`=(9xx9.46xx10^(15))/(3.084xx10^(16)) par sec`
=2.76 par sec
`I = 3xx10^(11)m`
`theta = (I)/(r ) = (3xx10^(11))/(9xx9.46xx10^(15)) radian`
`=(3xx180xx60xx60xx10^(-4))/(9xx9.46 pi)` sec`
`theta = 0.73 sec`