A drop of olive oil of radius 0.3 mm spreads into a rectangular film of `30 cmxx15cm` on the water surface. Calculate the size of the oil molecule.

Answer

`2.51xx10^(-9)m`

Explanation

`d = ("Volume of drop")/("Area of film") = ((4)/(3)pir^3)/(ixxb)`
`=(4)/(3)xx(22)/(7) (0.3xx10^(-3))^3/(30xx15xx10^(-4)) = 2.51xx10^(-9)m`