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An air moleculle spins once in 10^(-12)s...

An air moleculle spins once in `10^(-12)`s. How many times (order of mangitude) would an air molecule spin around its asixs, while the earth revolves once around the sun?

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Verified by Experts

The correct Answer is:
`10^(19)`
Time taken by earth to revolve once around the
sun = 365 days = `365.25xx24xx60xx60s`
Time fo spin `= 10^(-12)s`.
No. of spins ` =(365.25xx24xx60xx60)/(10^(-12))`
`=3.16xx10^(19) ~~ 10^(19)`
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