If two atomic clocks, allowed to run for 60 years differ from eachother by 0.2s only, calculate the accuracy of standerd atomic clock measuring a time interval of 1 sec.

Answer

`1 par in 10^(10)`

Explanation

As per question,
errro in measuring 60 years` (60xx365.25xx24 xx60xx60s) = 0.2s`
error in measuring 1 sec
`=(0.2)/(60xx365.25xx24xx60xx60)`
`= 1.056xx10^(-10)s`
:. Accuracy is 1 par in `10^(10)`