In the equation y= a sin `(omega t+ kx)` t and x stand for time and distance respectively. What are the dimensions of `omega//k`?

Answer

`LT^(-1)`

Explanation

The given equation is `y =a sin (omega t - kx)`
As angle is dimensionless, therefore,
`(omegat- kx)` = angle
`omega =(1)/(t) = T^(-1) and k = (1)/(k) = L^(-1)`
`(omega)/(k) = (T^(-1))/(L^(-1)) = [LT^(-1]`