Write the dimensions of `a//b` in the relation `F = a sqrtx + bt^2` where F is force x is distance and t is time.

Answer

`[L^(-1//2) T^2]`

Explanation

`asqrtx` has the dimensions of force F
`:. a = F|sqrtx = MLT^(-2) / L^(1//2) = M^1 L^(1//2) T^(-2)`
Similarly,
`b = F|t^2 = MLT^(-2)|T^2 = M^1L^1T^(-4)`
`:. (a)/(b) = (ML^(1//2)T^(-2))/(MLT^(-4)) = [L^(-1//2T^2)]`