Find the dimensions of `a//b` in the relation `P =(b-x^2)/(at)` where P is pressure. X is distance and t is time.

Answer

`M^(-1)LT`

Explanation

The given relation is
`P =(b-x^2)/(at) :. b=x^2 = [L^2]`
Also, `atxxP =x^2`
`a = (x^2)/(Pxxt) = (L^2)/([ML^(-1)T^(-2)]T) = [M^(-1)L^3 T]`
`(a)/(b) = [M^(-1) L^3 T]/(L^2) = [M^(-1) LT]`