The frequency (V) of an oscillatingj drop may depends upon radius (r ) of the drop density `(rho)` of liquid and the surface tension (S) of the liquid. Deduce of formula dimensionally.

Surface tension of a liquid depends upon .

A spherical liquid drop is placed on a horizontal plane . A small distrubance cause the volume of the drop to oscillate . The time period oscillation (T) of the liquid drop depends on radius (r) of the drop , density (rho) and surface tension tension (S) of the liquid. Which amount the following will be be a possible expression for T (where k is a dimensionless constant)?

The time period (t) of vibration of a liquid drop depends on surface tension (s),radius ( r) of the drop and density (rho) of the liquid .Find t.

If the time period (T) of vibration of a liquid drop depends on surface tension (S) , radius ( r ) of the drop , and density ( rho ) of the liquid , then find the expression of T .

The work done to split a liquid drop id radius R into N identical drops is (taken sigma as the surface tension of the liquid)

Time period of an oscillating drop of radius r, density rho and surface tension T is t=ksqrt((rhor^5)/T) . Check the correctness of the relation

A liquid drop of radius R breaks into 64 tiny droplets each of radius r if the surface tension of liquid is T then gain in energy is

Time period of an oscillating drop of radius r, density rho and surface tension S is t = K sqrt((rho r^3)/(S)) . Check the correctness of this relation