The specific heats of a gas are measured as `C_p = (12.28 +-0.2)` units and C_(upsilon =(3.97 +- 03)` units. Find the value of gas constant R and percentage error in R.

Answer

`(8.31 +- 0.5) units ; +- 6.016 %`

Explanation

Here, `C_p =(12.28 +- 0.2) units`
`C_(upsilon) = (3.97 +- 0.3) units`
`R = C_p - C_(upsilon)`
`=(12.28 - 3.97) +- (0.2 + 0.3)`
`=(8.31 +- 0.5 units`
Percentage error in R
`=(DeltaR)/(R )xx100 = ((Delta C_p +DeltaC_(upsilon))/(C_p - C_(upsilon)) xx100)`
`=((0.2+0.3))/(8.31)xx100 = +-6.016%`