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Time taken by a body in (20 +-0.2) secon...

Time taken by a body in `(20 +-0.2)` second in undergoing a displacement of `(200 +-5)`m. Calculate the percentage error in calculation of velcoity.

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Verified by Experts

The correct Answer is:
`+- 3.5%`
`upsilon =(s)/(t) = (200)/(20) =10m//s`
`(Deltaupsilon)/(upsilon)xx100 = +-((Deltas)/(s) +(Detlat)/(t))xx100`
`=+-((5)/(200) +(0.2)/(20))xx100`
`=+- (2.5+1) =+-3.5%`
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