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The error in the measurement of radius o...

The error in the measurement of radius of a sphere in `+-4%` What would be the error in volume of the sphere?

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Verified by Experts

The correct Answer is:
`+-12%`
Here, `(Deltar)/(r ) = +-4%`
As volume `V = (4)/(3) pi r^3`
`:. (DeltaV)/(V) =+-3((Deltar)/(r )) = +-3xx4% = +-12%`
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