Time taken by light to cross nuclear diameter is of the order of

Options

A. `10^(22)s`
B. `10^(-6)s`
C. `10^(-14)s`
D. `10^(-22)s`

Answer

To find the time taken by light to cross the diameter of a nucleus, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Formula**:
We start with the formula relating distance, speed, and time:
\[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \]
Rearranging this gives us:
\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]

2. **Determine the Distance**:
The diameter of a nucleus is typically on the order of \(10^{-15}\) meters (1 femtometer).

3. **Identify the Speed of Light**:
The speed of light in a vacuum is approximately \(3 \times 10^8\) meters per second.

4. **Substitute the Values**:
Now we can substitute the values into the time formula:
\[ \text{Time} = \frac{10^{-15} \text{ m}}{3 \times 10^8 \text{ m/s}} \]

5. **Calculate the Time**:
Performing the division:
\[ \text{Time} = \frac{1}{3} \times 10^{-15} \times 10^{-8} = \frac{1}{3} \times 10^{-23} \text{ seconds} \]

6. **Approximate the Result**:
The value \(\frac{1}{3} \times 10^{-23}\) can be approximated as:
\[ \approx 0.33 \times 10^{-23} \text{ seconds} \]
This can also be expressed in terms of powers of ten:
\[ 0.33 \times 10^{-23} = 3.3 \times 10^{-24} \text{ seconds} \approx 10^{-22} \text{ seconds} \]

7. **Final Answer**:
Therefore, the time taken by light to cross the nuclear diameter is of the order of:
\[ 10^{-22} \text{ seconds} \]