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Given that y = a cos((t)/(P) - qx), wher...

Given that `y = a cos((t)/(P) - qx),` where t represents distance is metre. Which of the following statements is true ?

A

unit of t is same as that of p

B

unit of t is same as that of q

C

unit of x is same as that of q

D

unit of x is same as that of P

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The correct Answer is:
To analyze the given equation \( y = a \cos\left(\frac{t}{P} - qx\right) \), we need to determine the relationships between the variables \( t \), \( x \), \( P \), and \( q \). ### Step-by-Step Solution: 1. **Identify the Variables:** - \( y \): Displacement (not specified in units, but typically in meters). - \( a \): Amplitude (also typically in meters). - \( t \): Represents distance in meters. - \( P \): A constant that we need to analyze. - \( q \): A constant that we need to analyze. - \( x \): Another variable (distance) in meters. 2. **Analyze the Argument of the Cosine Function:** - The argument of the cosine function is dimensionless. Therefore, the expression \( \frac{t}{P} - qx \) must also be dimensionless. - This implies that both \( \frac{t}{P} \) and \( qx \) must have the same dimensions. 3. **Determine the Dimensions:** - Since \( t \) is in meters, the dimension of \( t \) is [L]. - For \( \frac{t}{P} \) to be dimensionless, \( P \) must also have the dimension of length [L]. - Thus, we conclude that the dimensions of \( t \) and \( P \) are the same. 4. **Analyzing \( qx \):** - Since \( qx \) must also be dimensionless, \( q \) must have dimensions that are the inverse of \( x \). - Given that \( x \) is in meters, the dimension of \( q \) must be [L]⁻¹ (inverse length). 5. **Summarize the Relationships:** - From the analysis, we have: - The unit of \( t \) is the same as that of \( P \) (both are in meters). - The unit of \( q \) is not the same as that of \( t \) or \( P \) (it is in [L]⁻¹). - The unit of \( x \) is the same as that of \( t \) and \( P \) (both are in meters). 6. **Conclusion:** - The correct statement is that the unit of \( t \) is the same as that of \( P \). ### Final Answer: The true statement is: **The unit of \( t \) is the same as that of \( P \)**.

To analyze the given equation \( y = a \cos\left(\frac{t}{P} - qx\right) \), we need to determine the relationships between the variables \( t \), \( x \), \( P \), and \( q \). ### Step-by-Step Solution: 1. **Identify the Variables:** - \( y \): Displacement (not specified in units, but typically in meters). - \( a \): Amplitude (also typically in meters). - \( t \): Represents distance in meters. ...
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