If the dimensions of a physical quantity are given by `M^(a)L^(b)T^(c)`, then the physical quantity will be :

Options

A. force, if a = 0, b= -1, c =-2
B. pressure, if a= 1, b =-1, c= -2
C. velocity, if a = 1, b= 0, c= -1
D. acceleration, if a= 1, b= 1, c= -2

Answer

(b)

Explanation

Pressure =` ("force")/("area")` = `(MLT^(-2))/(L^2) = [M^1 L^(-1) T^(-2)]`
`:. a = 1, b= -1 c =-2`
Choice (b) is correct.