The position x of a partical at time t is given by `x =(V_0)/(a) (1 -e^(9-at))` where `V_0` is a constant and a gt 0. The dimensions of `V_0` and a are.

Options

A. `M^0 L T^(-1) and T^(-1)`
B. `M^0 L T^0 and T^(-1)`
C. `M^0 L T^(-1) and L T^(-2)`
D. `M^0 L T^(-1) and T`

Answer

(a)

Explanation

As axxt is dimensionless.
`:. a = (1)/(t) = (1)/(T) = [T^(-1)]`
Also,` x = (V_0)/(a), V_0 = x a = [LT^(-1)]`