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In terms of basic units of mass (M), len...

In terms of basic units of mass (M), length (L), time (T), and charge (Q), the dimensions of magnetic permeability of vacuum `(mu_0)` would be

A

`(MLQ^(-2))`

B

`(LT^(-1) Q^(-1))`

C

`(ML^2 T^(-1)Q^(-2))`

D

`(LTQ^(-1))`

Text Solution

Verified by Experts

The correct Answer is:
(a)
Force acting per unit length of eacth of two parallel wires carrying currents in the same direction placed certain distance apart in vacuum is
`(F)/(I) = (mu_0)/(4pi). (2I_1II_2)/(r )`
`(MLT^(-2))/(L) = mu_0 ((Q//T)^2)/(L) or mu_0 = [MLQ^(-2)]`
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