Dimensions of `ohm` are same as that of (where h is Planck's constant and e is charge)

Options

A. `h//e`
B. `h^2//e`
C. `h//e^2`
D. `h^2//e^2`

Answer

(c )

Explanation

`(h)/(e^2) = (ML^2 T^(-1))/((AT)^2) = ML^2 T^(-3) A^(-2)`
=Resistance (ohm)