The length of a cylinder is measured with a meter rod having least count `0.1 cm`. Its diameter is measured with Vernier calipers having least count `0.01 cm`. Given that length is `5.0 cm` and radius is ` 2 cm`. Find the percentage error in the calculated value of the volume.

Options

A. 0.04
B. 0.03
C. 0.02
D. 0.01

Answer

(b)

Explanation

Here, I = 5.0 cm, r = 2.00 cm
Also `Delta I rarr` least count of meter rod = 0.1 cm
`Delta r rarr` Vernier constant = 0.01 cm
`V(Volume)= pi r^2 I`
`:. (DeltaV)/(V) = 2((Delta r)/(r )) + (DeltaI)/(I) = 2xx((0.01)/(2.00)) + (0.1)/(5.0)`
=0.03
`% error = (Delta V)/(V) xx100 = 0.03 xx100 = 3%`