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1 cm on the main scale of a vernier call...

`1 cm` on the main scale of a vernier callipers is divided into `10 equal` parts. If `10` divisions of vernier coincide with `8` small divisions of main scale, then the least count of the calliper is.

A

0.01 cm

B

0.02 cm

C

0.05 cm

D

0.005 cm

Text Solution

Verified by Experts

The correct Answer is:
(b)
`1 MSD = (1)/(10)cm` .
`L.C = 1MSD - 1 VSD = (1 -(8)/(10))MSD`
`=(1)/(5)MSD = (1)/(50)cm = 0.02 cm`
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