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In an experiment four quantities a,b,c a...

In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is

A

0.04

B

0.14

C

0.1

D

0.07

Text Solution

Verified by Experts

The correct Answer is:
(b)
Here, `P = (a^3 b^2)/(cd)`
`(DeltaP)/(P) = +-(3(Delta a)/(a) + 2 (Delta b)/(b) + (Delta c)/(c ) + (Delta d)/(d))`
`(Delta P)/(P)xx100 = +- (3xx 1% + 2xx 2% +3% + 4%)`
`= +- 14%`
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