A car (A) is moving at `60 km h^(-1)` on a straight road, is ahead of car (B) moving in the same direction at `10 ms^(-1)`. Find the velocity of (A) relative to (B) and vice versa.

Explanation

Here, `v_(A) =60 km h^(-1)`
`=(60 xx 1000 m)/(60 xx 60 s) =(50)/3 m//s :`
`v_(B) =10 ms^(-1)`
Velocity of (A) value of `v_(AB)` indicates that the person sitting in car (B) sees car (A) moving ahead from him at the rate of `6.67 ms^(-1)`.
Velocity of (B) respect to `A, v_(BA)` =v_(B) -v_(A)`
`=10 -(50)/3 =- (20)/3 =- 6. 67 ms^(-1)`
Negative value of `v_(BA)` indicates that the person sittion in (A) sees the car (B) lagging behind at the rate of `6.67 ms^(-1)`.