A jet plane is flying horizontally with a velocity `600 km h^(-1)`. The burnt gases are injecting from the rear of the get plane with the velocity `2000 km h^(-1)`. With respect to the jet plane. Find the velocity of burnt gases with respect to a person on the ground.

Explanation

Let the motion along +ve x-direction be taken positive and motion alon-ve x-direction be negativ.
Let the jet plane be moving along positive x-direction. The burnt gases will be moving along negatibe x-direction. Therefore,
velocity of place, `v_(j) =600 km h^(-1)`
velcoty of burnt gases with respect to jet plane
`v_(gj) =v_(g) v_(j) =- 2000 km h^(-1)`
or `v_(g) =- 2000 km h^(-1) +v_(j) =-2000 + 600 `
`=- 1400 km h^(-1)`
The velcity of burnt gases w,r,t, person standing onthe ground `=(|v_(g) -v_(G) )= - 1400 -0
`= - 1400 km h^(-1)`.