Two buses `A and B` are at positions `60 m` 160 m` from the origin at time `t=0`. They start moving in the same direction simultaneously with uniform speed `54 km h^(-1)` and `36 km h^(-`)`. Derermine the time and positiona t which `A overtaken B`.

Explanation

To solve the problem of when bus A overtakes bus B, we can follow these steps:

### Step 1: Convert Speeds to Meters per Second
First, we need to convert the speeds of both buses from kilometers per hour to meters per second.

- Speed of bus A:
\[
V_A = 54 \text{ km/h} = 54 \times \frac{1000 \text{ m}}{3600 \text{ s}} = 15 \text{ m/s}
...